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Django中利用js来操作数据的常规操作一般为点(.)操作符来获取字典或列表的数据,一般如{{data.0}},{{data.arg}}
但有时如果数据是嵌套类型的数据时,直接获取某个值就变得困难了,比如下面的格式要获取
correct中qxl的值
startArgsSet={"correct":{"qxl":0,"kkx":0},"reliable":{"qxl":0,"kkx":0},"security":{"qxl":0,"kkx":0},"understand":{"qxl":0,"kkx":0},"entropy":{"qxl":0,"kkx":0}, "mature":{"qxl":0,"kkx":0},"active":{"qxl":0,"kkx":0},"service":{"qxl":0,"kkx":0},"file":{"qxl":0,"kkx":0}, "tech":{"qxl":0,"kkx":0},"property":{"qxl":0,"kkx":0},"organize":{"qxl":0,"kkx":0},"develop":{"qxl":0,"kkx":0}, "source":{"qxl":0,"kkx":0},"update":{"qxl":0,"kkx":0},"fix":{"qxl":0,"kkx":0}, "quality":{"qxl":0,"kkx":0},"meanNum":{"qxl":0,"kkx":0},"variance":{"qxl":0,"kkx":0} }
这时候如果改变数据格式为列表中的无嵌套字典格式比较麻烦,可以自定义过滤器来获取数据,
from django.template.defaulttags import register @register.filter def getArgQxlValue(dictionary,arg): return dictionary[arg]['qxl'] @register.filter def getArgKkxValue(dictionary,arg): return dictionary[arg]['kkx'] @register.filter def getArgName(dictionary,arg): return dictionary[arg]['name']
在模板中就可以以这样写
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